SOLUTION: Find all solutions of the equation 2 cos 3x = 1 in the interval [0,pi), with x1<x2<x3.

Algebra ->  Trigonometry-basics -> SOLUTION: Find all solutions of the equation 2 cos 3x = 1 in the interval [0,pi), with x1<x2<x3.       Log On


   

Question 927958: Find all solutions of the equation 2 cos 3x = 1 in the interval [0,pi), with x1
Answer by brysca(112) About Me  (Show Source):
You can put this solution on YOUR website!
solution posted below
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hope this helps!
Response to comment:
Since they're asking for a third answer ask again, when does cos(z)=1/2?
cos(z) would equal 1/2 when z equals 7pi%2F3
Plug into the equation: 3x=z
3x=7pi%2F3
x=7pi%2F9
Since the equation's domain is up to pi, this is why they ask for the third solution. The next solution for x would be 11pi%2F9 but this is wrong since 11pi%2F9 is greater than pi. 11pi%2F9 exceeds the domain restrictions.