SOLUTION: Write the complex number z = 2 + 6i in polar form: z = r(cos theta + i sin theta) where r=? and theta=?. The angel should satisfy 0<=theta<2pi.
Found r which is sqrt(40) but cant
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-> SOLUTION: Write the complex number z = 2 + 6i in polar form: z = r(cos theta + i sin theta) where r=? and theta=?. The angel should satisfy 0<=theta<2pi.
Found r which is sqrt(40) but cant
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Question 927953: Write the complex number z = 2 + 6i in polar form: z = r(cos theta + i sin theta) where r=? and theta=?. The angel should satisfy 0<=theta<2pi.
Found r which is sqrt(40) but cant find theta. Please help! Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Write the complex number z = 2 + 6i in polar form: z = r(cos theta + i sin theta) where r=? and theta=?. The angel should satisfy 0<=theta<2pi.
Found r which is sqrt(40) but cant find theta.
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theta = tan-1(6/2)
