Question 927951: Find all values of theta.
sin^2(2theta)-sin(2theta)-2=0
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find all values of theta.
sin^2(2theta)-sin(2theta)-2=0
use x for theta:
sin^2(2x)-sin(2x)-2=0
sin(2x)-2)(sin(2x)+1)=0
sin(2x)-2=0
sin(2x)=2 (reject, (-1 ≤ sin(2x) ≤ 1))
or
sin(2x)+1=0
sin(2x)=-1
2x=π+2πn, n=any integer
x=π/2+2πn,n=any integer
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