SOLUTION: The following table gives the total caseload (in millions) in a state's courts from 2004 through 2009. Year 2004 2005 2006 2007 2008 20

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Question 927544: The following table gives the total caseload (in millions) in a state's courts from 2004 through 2009.
Year 2004 2005 2006 2007 2008 2009
Cases 4.2 4.7 4.8 4.5 4.1 4.1
Find the mean of the total caseload for the state's courts from 2004 through 2009. (Round your answer to two decimal places.)

Correct: Your answer is correct.
4.4 million cases
What is the standard deviation for these data? (Round your answer to two decimal places.)
Found 2 solutions by Techpriest, ewatrrr:
Answer by Techpriest(29) About Me  (Show Source):
You can put this solution on YOUR website!
To find the mean, we add up all of the sum of the numbers and divide by how many of the numbers are there.
+4.2+%2B+4.7+%2B+4.8+%2B+4.5+%2B+4.1+%2B+4.1+=+26.4+
+26.4%2F6+=+4.4+
To find the standard deviation of the mean which is 4.4, we find the distance of the numbers shown above and subtract it by the mean by also making sure that the answer is an absolute value.
|4.4 - 4.2| = 0.2
|4.4 - 4.7| = 0.3
|4.4 - 4.8| = 0.4
|4.4 - 4.5| = 0.1
|4.4 - 4.1| = 0.3
|4.4 - 4.1| = 0.3
Adding up the answers above and divide it by how many of the answers are there.
+0.2+%2B+0.3+%2B+0.4+%2B+0.1+%2B+0.3+%2B+0.3+=+1.6+
+1.6%2F6+=+0.266666+
So the standard deviation is about 0.27.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

	x	x -4.4	(x-4.4)^2

	4.2	-0.2	0.04

	4.7	0.3	0.09

	4.8	0.4	0.16

	4.5	0.1	0.01

	4.1	-0.3	0.09

	4.1	-0.3	0.09

sum	26.4		0.48

mean	4.4	.48/6	0.08  Variance

		sqrt(.08) = SD=0.282842712

Note: IF .48/5  then SD = .30984