SOLUTION: Find the exact values of sin(&#952;/2), cos(&#952;/2), and tan(&#952;/2) for the given conditions. sec &#952; = &#8722; 3/2; 180° < &#952; < 270° sin(&#952;/2) = cos(

Algebra ->  Trigonometry-basics -> SOLUTION: Find the exact values of sin(&#952;/2), cos(&#952;/2), and tan(&#952;/2) for the given conditions. sec &#952; = &#8722; 3/2; 180° < &#952; < 270° sin(&#952;/2) = cos(      Log On


   

Question 927500: Find the exact values of sin(θ/2), cos(θ/2), and tan(θ/2) for the given conditions.
sec θ = − 3/2; 180° < θ < 270°
sin(θ/2) =
cos(θ/2) =
tan(θ/2) =

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the exact values of sin(θ/2), cos(θ/2), and tan(θ/2) for the given conditions.
sec θ = − 3/2; 180° < θ < 270°
sin(θ/2) =
cos(θ/2) =
tan(θ/2) =
***
secx=-3%2F2
cosx=-2%2F3180° < θ < 270°
sin%28x%2F2%29=sqrt%28%281-cosx%29%2F2%29=sqrt%281%2B%282%2F3%29%2F2%29=sqrt%285%2F6%29
cos%28x%2F2%29=-sqrt%28%281%2Bcosx%29%2F2%29=-sqrt%281-%282%2F3%29%2F2%29=-sqrt%281%2F6%29
tan%28x%2F2%29=sin%28x%2F2%29%2Fcos%28x%2F2%29=-sqrt%285%29