Question 927455: Mr. Sanchez makes a business trip from his house to the city in 2 hours. One hour later, he returns home in heavy traffic at a rate of 20 kph(kilometers per hour) less than his going rate. If Mr. Sanchez was gone a total of 6 hours, how fast did he travel on each of the trip?
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! s = d/t
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outbound:
t = 2 hrs
x = outbound speed
x = d/2
d = 2x
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return:
he's in the city for 1 hour (not traveling during that 1 hr)
t = 6 - 2 - 1 = 3 hrs
y = return speed
y = x - 20
y = d/3
d = 3y
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2x = 3y
2x = 3(x - 20)
2x = 3x - 60
x = 60
y = x - 20
y = 60 - 20
y = 40
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answer:
x = outbound speed = 60 kph
y = return speed = 40 kph
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