It has to be one of these: 14, 25, 36, 47, 58, or 69.
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The units digit of a two digit number is 3 more than the tens digit.
In place of those red words, write simply u.
u is 3 more than the tens digit.
In place of those red words, write simply t.
u is 3 more than t.
In place of those red words, write t+3, because to get 3 more than
something you add 3 to it.
u is t+3
Change the red word is to =
u = t+3
That's the first equation. Now we get the second equation:
the sum of the digits is 16 less than one-half the number
Replace those red words by t+u
t+u is 16 less than one-half the number
Replace those red words by (10t+u).
t+u is 16 less than one-half (10t+u).
Replace that red hyphenated word by 
.
t+u is 16 less than 
(10t+u).
In place of those red words, write (10t+u)-16, because to
get 16 less than something you subtract 16 from it.
t+u is (10t+u)-16
Change the red word is to =
t+u = (10t+u)-16
Now we have both equations. Now solve the system of equations:
.
Can you solve that system of equations? If not, you may ask how
in the thank-you note form below.
Edwin
