Question 927362: You roll a fair die three times. What is the probability that
a) you roll all 6's?
b)you roll all odd numbers?
c) none of your rolls gets a number divisible by 3?
d) you roll at least one 5?
e) the numbers you roll are not all 5's?
For A, is the answer (1/216)? And is B, (1/8)?
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website! rolling a fair die 6 outcomes: 1,2,3,4,5,6
rolling a fair die three times
....
P(all 6's) = (1/6)^3 = 1/216
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P(all odd numbers) = P( 1 0r 3 0r 5)= (1/2)^3 = 1/8
...
P(number divisible by 3) = P( 3 0r 6) = (1/3)^3 = 1/27
........
P(least one 5) = 1 - P( no 5's) = 1 - (5/6)^3 = 1 - .5787 = .4213
.......
P(numbers you roll are not all 5's)= 1 - P(all fives) = 1 - (1/6)^3 = 1 - 1/216 = 215/216
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