SOLUTION: The electrical resistance R of a wire varies directly as its length L and inversely as the square of its diameter. A wire 20 meters long and 0.6 centimeters in diameter made from a

Algebra ->  Trigonometry-basics -> SOLUTION: The electrical resistance R of a wire varies directly as its length L and inversely as the square of its diameter. A wire 20 meters long and 0.6 centimeters in diameter made from a      Log On


   



Question 92734This question is from textbook Algebra and Trigonometry
: The electrical resistance R of a wire varies directly as its length L and inversely as the square of its diameter. A wire 20 meters long and 0.6 centimeters in diameter made from a certain alloy has a resistance of 36 ohms. What is the resistance of a piece of wire 60 meters long and 1.2 centimeters in diameter made from the same material? This question is from textbook Algebra and Trigonometry

Answer by psbhowmick(878) About Me  (Show Source):
You can put this solution on YOUR website!
R%5B1%5D+=+k%5B1%5DL%5B1%5D%2Fd%5B1%5D%5E2 ___________ (1)
where R%5B1%5D (in Ohm) = resistance of the first electrical wire of length = L%5B1%5D (in metre) and diameter = d%5B1%5D (in centimetre) and k%5B1%5D = constant of variation with appropriate units

Similarly, R%5B2%5D+=+k%5B2%5DL%5B2%5D%2Fd%5B2%5D%5E2 __________ (2)
where R%5B2%5D (in Ohm) = resistance of the second electrical wire of length = L%5B2%5D (in metre) and diameter = d%5B2%5D (in centimetre) and k%5B2%5D = constant of variation with appropriate units
Dividing equation (1) by equation (2)

As both the wires are of same material k%5B1%5D+=+k%5B2%5D
So, R%5B2%5D%2FR%5B1%5D+=+%28L%5B2%5Dd%5B1%5D%5E2%29%2F%28L%5B1%5Dd%5B2%5D%5E2%29 _________ (3)

Here L%5B1%5D+=+20, d%5B1%5D+=+0.6, R%5B1%5D+=+36, L%5B2%5D+=+60 and d%5B2%5D+=+1.2

Then, from substituting these values in equation (3)
R%5B2%5D%2F36+=+%2860%2A0.6%5E2%29%2F%2820%2A1.2%5E2%29
R%5B2%5D%2F36+=+3%2F4
R%5B2%5D+=+%283%2A36%29%2F4
R%5B2%5D+=+27