SOLUTION: On a hill, inclined at an angle of 14.2o with the horizontal stands a vertical tower. At a point P, 62.5 meters down the hill from the foot of the tower, the angle of elevation of

Algebra ->  Triangles -> SOLUTION: On a hill, inclined at an angle of 14.2o with the horizontal stands a vertical tower. At a point P, 62.5 meters down the hill from the foot of the tower, the angle of elevation of       Log On


   



Question 927333: On a hill, inclined at an angle of 14.2o with the horizontal stands a vertical tower. At a point P, 62.5 meters down the hill from the foot of the tower, the angle of elevation of the top of the tower is 43.6o . How tall is the tower?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Here is a sketch with the necessary imaginary horizontal and vertical lines drawn in green:
We need to calculate h , the height of tower BT .
We can use law of sines applied to triangle BPT:
h%2Fsin%28BPT%29=62.5m%2Fsin%28PTB%29
We just need to calculate the measure of those angles
BPT=43.6%5Eo-14.2%5Eo=29.4%5Eo
and PTB is part of right triangle PTU, so
PTB=90%5Eo-43.6%5Eo=46.4%5Eo
So, h%2Fsin%2829.4%5Eo%29=62.5m%2Fsin%2846.4%5Eo%29
Using approximate values,
h%2F0.490904=62.5m%2F0.724172
h=0.490904%2A62.5m%2F0.724172
highlight%28h=42.4m%29 (rounded to one decimal place).