SOLUTION: write an equation in standard form of a line that is perpendicular to the line 7x+3y=18 and contains the point (6,8). how do u solve this?

Algebra ->  Linear-equations -> SOLUTION: write an equation in standard form of a line that is perpendicular to the line 7x+3y=18 and contains the point (6,8). how do u solve this?      Log On


   

Question 927230: write an equation in standard form of a line that is perpendicular to the line 7x+3y=18 and contains the point (6,8).

how do u solve this?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
First convert to slope-intercept form.
3y=-7x%2B18
y=-%287%2F3%29x%2B6
Perpendicular lines have slopes that are negative reciprocals,
-%287%2F3%29%2Am%5Bp%5D=-1
m%5Bp%5D=3%2F7
Now use the point-slope form of a line with the point (6,8),
y-8=%283%2F7%29%28x-6%29
7y-56=3x-18
-3x%2B7y=38
highlight%283x-7y=-38%29