Question 927161: In a group of 14 students, there are 8 girls and 6 boys.
a) Determine the number of ways that a committee of 4 students can be chosen from this group.
b) Determine the number of ways that a committee of 4 students which has exactly 2 girls can be chosen from the group.
c) Determine the number of ways that a committee of 4 students which has at least 1 boy can be chosen from the group.
d) The committee of 4 students must have 1 girl, 1 boy , and 2 other students, how many different committees can be chosen from this group?
I have solved a), b) and c) for the question, but I am not sure about d).
I thought maybe it could be worked out like this:
8C1 x 6C1 x 12C2 = 3,168
I don't know if that is right though. Any help would be greatly appreciated. Thank you!
Found 2 solutions by ewatrrr, stanbon:
Answer by ewatrrr(24785)   (Show Source):
Answer by stanbon(75887)  (Show Source):
You can put this solution on YOUR website! In a group of 14 students, there are 8 girls and 6 boys.
a) Determine the number of ways that a committee of 4 students can be chosen from this group.
b) Determine the number of ways that a committee of 4 students which has exactly 2 girls can be chosen from the group.
c) Determine the number of ways that a committee of 4 students which has at least 1 boy can be chosen from the group.
d) The committee of 4 students must have 1 girl, 1 boy , and 2 other students, how many different committees can be chosen from this group?
I have solved a), b) and c) for the question, but I am not sure about d).
I thought maybe it could be worked out like this:
8C1 x 6C1 x 12C2 = 3,168
----
Comment:: Since all of the "other students" are either boys or girls,
I think your answer is correct..
Cheers,
Stan H.
--------------------
|
|
|
