SOLUTION: 2x-3y+2z=6 x+8y+3z=-31 3x-2y+z=-5

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Question 927155: 2x-3y+2z=6
x+8y+3z=-31
3x-2y+z=-5

Found 2 solutions by ewatrrr, Fombitz:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
2x-3y+2z=6
x+8y+3z=-31
3x-2y+z=-5
Ordered Triple (-5, -4, 2) the Solution for this System
Solved by pluggable solver: Using Cramer's Rule to Solve Systems with 3 variables



system%282%2Ax%2B-3%2Ay%2B2%2Az=6%2C1%2Ax%2B8%2Ay%2B3%2Az=-31%2C3%2Ax%2B-2%2Ay%2B1%2Az=-5%29



First let A=%28matrix%283%2C3%2C2%2C-3%2C2%2C1%2C8%2C3%2C3%2C-2%2C1%29%29. This is the matrix formed by the coefficients of the given system of equations.


Take note that the right hand values of the system are 6, -31, and -5 and they are highlighted here:




These values are important as they will be used to replace the columns of the matrix A.




Now let's calculate the the determinant of the matrix A to get abs%28A%29=-48. To save space, I'm not showing the calculations for the determinant. However, if you need help with calculating the determinant of the matrix A, check out this solver.



Notation note: abs%28A%29 denotes the determinant of the matrix A.



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Now replace the first column of A (that corresponds to the variable 'x') with the values that form the right hand side of the system of equations. We will denote this new matrix A%5Bx%5D (since we're replacing the 'x' column so to speak).






Now compute the determinant of A%5Bx%5D to get abs%28A%5Bx%5D%29=240. Again, as a space saver, I didn't include the calculations of the determinant. Check out this solver to see how to find this determinant.



To find the first solution, simply divide the determinant of A%5Bx%5D by the determinant of A to get: x=%28abs%28A%5Bx%5D%29%29%2F%28abs%28A%29%29=%28240%29%2F%28-48%29=-5



So the first solution is x=-5




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We'll follow the same basic idea to find the other two solutions. Let's reset by letting A=%28matrix%283%2C3%2C2%2C-3%2C2%2C1%2C8%2C3%2C3%2C-2%2C1%29%29 again (this is the coefficient matrix).




Now replace the second column of A (that corresponds to the variable 'y') with the values that form the right hand side of the system of equations. We will denote this new matrix A%5By%5D (since we're replacing the 'y' column in a way).






Now compute the determinant of A%5By%5D to get abs%28A%5By%5D%29=192.



To find the second solution, divide the determinant of A%5By%5D by the determinant of A to get: y=%28abs%28A%5By%5D%29%29%2F%28abs%28A%29%29=%28192%29%2F%28-48%29=-4



So the second solution is y=-4




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Let's reset again by letting A=%28matrix%283%2C3%2C2%2C-3%2C2%2C1%2C8%2C3%2C3%2C-2%2C1%29%29 which is the coefficient matrix.



Replace the third column of A (that corresponds to the variable 'z') with the values that form the right hand side of the system of equations. We will denote this new matrix A%5Bz%5D






Now compute the determinant of A%5Bz%5D to get abs%28A%5Bz%5D%29=-96.



To find the third solution, divide the determinant of A%5Bz%5D by the determinant of A to get: z=%28abs%28A%5Bz%5D%29%29%2F%28abs%28A%29%29=%28-96%29%2F%28-48%29=2



So the third solution is z=2




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Final Answer:




So the three solutions are x=-5, y=-4, and z=2 giving the ordered triple (-5, -4, 2)




Note: there is a lot of work that is hidden in finding the determinants. Take a look at this 3x3 Determinant Solver to see how to get each determinant.



Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!

Cramer's rule
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A=%28matrix%283%2C3%2C%0D%0A2%2C-3%2C2%2C%0D%0A1%2C8%2C3%2C%0D%0A3%2C-2%2C1%29%29
abs%28A%29=-48
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A%5Bx%5D=%28matrix%283%2C3%2C%0D%0A6%2C-3%2C2%2C%0D%0A-31%2C8%2C3%2C%0D%0A-5%2C-2%2C1%29%29
abs%28A%5Bx%5D%29=-48
.
.
A%5By%5D=%28matrix%283%2C3%2C%0D%0A2%2C6%2C2%2C%0D%0A1%2C-31%2C3%2C%0D%0A3%2C-5%2C1%29%29
abs%28A%5By%5D%29=-48
.
.
.
A%5Bz%5D=%28matrix%283%2C3%2C%0D%0A2%2C-3%2C6%2C%0D%0A1%2C8%2C-31%2C%0D%0A3%2C-2%2C-5%29%29
abs%28A%5Bz%5D%29=-48
.
.
..
x=abs%28A%5Bx%5D%29%2Fabs%28A%29=%28240%29%2F%28-48%29=-5
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y=abs%28A%5By%5D%29%2Fabs%28A%29=%28192%29%2F%28-48%29=-4
.
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z=abs%28A%5Bz%5D%29%2Fabs%28A%29=%28-96%29%2F%28-48%29=2