SOLUTION: FIND TWO NUMBERS IF THREE TIMES THE SECOND NUMBER EXCEEDS SEVEN TIMES THE FIRST BY 3.FIVE TIMES THE FIRST INCREASED BY ONE IS EQUAL TO TWICE THE SECOND

Algebra ->  Human-and-algebraic-language -> SOLUTION: FIND TWO NUMBERS IF THREE TIMES THE SECOND NUMBER EXCEEDS SEVEN TIMES THE FIRST BY 3.FIVE TIMES THE FIRST INCREASED BY ONE IS EQUAL TO TWICE THE SECOND      Log On


   

Question 927113: FIND TWO NUMBERS IF THREE TIMES THE SECOND NUMBER EXCEEDS SEVEN TIMES THE FIRST BY 3.FIVE TIMES THE FIRST INCREASED BY ONE IS EQUAL TO TWICE THE SECOND
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

let numbers be x and y
3y=7x%2B3....eq.1
5x%2B1=2y....eq.2
___________________________
5x%2B1=2y....eq.2...solve for y
%285%2F2%29x%2B1%2F2=y....substitute in eq.1
3%28%285%2F2%29x%2B1%2F2%29=7x%2B3....eq.1.solve for x
%2815%2F2%29x%2B3%2F2=7x%2B3
7.5x=7x%2B3-1.5
7.5x-7x=1.5
0.5x=1.5....both sides multiply by 10 to get whole numbers
5x=15
x=15%2F5
highlight%28x=3%29
now, find y

y=%285%2F2%29x%2B1%2F2...plug in 3 for x
y=%285%2F2%293%2B1%2F2
y=%2815%2F2%29%2B1%2F2
y=7.5%2B0.5
highlight%28y=8%29