SOLUTION: Find the exact values of sin(&#952;/2), cos(&#952;/2), and tan(&#952;/2) for the given condition. csc &#952; = &#8722; 5/4; &#8722;90° < &#952; < 0° sin(&#952;/2) = cos(&#9

Algebra ->  Trigonometry-basics -> SOLUTION: Find the exact values of sin(&#952;/2), cos(&#952;/2), and tan(&#952;/2) for the given condition. csc &#952; = &#8722; 5/4; &#8722;90° < &#952; < 0° sin(&#952;/2) = cos(&#9      Log On


   

Question 926992: Find the exact values of sin(θ/2), cos(θ/2), and tan(θ/2) for the given condition.
csc θ = − 5/4; −90° < θ < 0°
sin(θ/2) =
cos(θ/2) =
tan(θ/2) =
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the exact values of sin(θ/2), cos(θ/2), and tan(θ/2) for the given condition.
csc θ = − 5/4; −90° < θ < 0°
sin(θ/2) =
cos(θ/2) =
tan(θ/2) =
***
reference angle θ is in quadrant IV where cos>0, sin<0
csc θ=-5/4
sin θ=-4/5
cos θ=3/5
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