SOLUTION: find three consecutive odd integers such that twice the first decreased by the second exceeds three times the third by 56

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Question 926972: find three consecutive odd integers such that twice the first decreased by the second exceeds three times the third by 56
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive odd integers: (x-2), x, (x+2)

2(x-2) - x = 3(x+2) + 56
(2x - 4) - x = (3x + 6) + 56
x - 4 = 3x + 62
-66 = 2x
x = -33


The integers are -35, -33, and -31.