SOLUTION: log2(1/square root 2)=?

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Question 926849: log2(1/square root 2)=?
Found 2 solutions by MathLover1, CharlesG2:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
log%282%2C%281%2Fsqrt+%282%29%29%29
...since sqrt%282%29=2%5E%281%2F2%29, we have

=log%282%2C%281%2F2%5E%281%2F2%29%29%29

=log%282%2C%282%5E%28-1%2F2%29%29%29

=-%281%2F2%29log%282%2C%282%29%29...........log%282%2C%282%29%29=1

=-%281%2F2%29

Answer by CharlesG2(834) About Me  (Show Source):
You can put this solution on YOUR website!
log2(1/square root 2)=?
log2 (1 / sqrt(2) ) = ?
1 / sqrt(2) = 1 / (2 ^ 1/2) = 2 ^ -1/2
log2 (2 ^ -1/2 ) = ?
log2 (2 ^ -1/2 ) = -1/2 = -0.5

y=b^x <==> x=logb(y)
example
8=2^3 <==> 3=log2 (8) which is same as 3 = log2 (2^3)