SOLUTION: divide 72 into two parts so that the larger part exceeds the smaller part by 12.find both parts

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Question 926481: divide 72 into two parts so that the larger part exceeds the smaller part by 12.find both parts
Answer by vleith(2983) About Me  (Show Source):
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You are asked to find two numbers with a sum of 72.
You are also told that one of the numbers is 12 greater than the other.
Let the smaller number be S.
Then the larger number is (S + 12)
S+%2B+%28S%2B12%29+=+72
+S+%2B+S+%2B+12+=+72
2S+%2B+12+=+72
2S+%2B12+-+12+=+72+-+12
2S+=+60
S+=+30
If S = 30, then S+12 = 42
Check your answer. Does 30 + 42 = 72??