SOLUTION: a dog trainer has 80 feet of fencing with which to create a rectangular area for dogs. if the trainer want to enclose an area of 300 ft square what will be the dimensions of the en

Algebra ->  Rectangles -> SOLUTION: a dog trainer has 80 feet of fencing with which to create a rectangular area for dogs. if the trainer want to enclose an area of 300 ft square what will be the dimensions of the en      Log On


   

Question 926383: a dog trainer has 80 feet of fencing with which to create a rectangular area for dogs. if the trainer want to enclose an area of 300 ft square what will be the dimensions of the enclosure
Answer by JulietG(1812) About Me  (Show Source):
You can put this solution on YOUR website!
Perimeter = 80
Area = 300
The easiest way to do this is to find the factors of 300 and then see which ones add up to 40 (half of 80 since P=2L + 2W).
Factors of 300:
1,300
2,150
3,100
4,75
5,60
10,30
12,25
15,20
Only 10 and 30 = 40
Width = 10, length = 30
10*30=300 sf area
10+10+30+30=80 perimeter