Question 926299: A rock is thrown upward with a velocity of 13 meters per second from the top of a 39 meter high cliff, and it misses the cliff on the way back down. When will the rock be 11 meters from the water below? Round answer to two decimal places.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! A rock is thrown upward with a velocity of 13 meters per second from the top of a 39 meter high cliff, and it misses the cliff on the way back down. When will the rock be 11 meters from the water below? Round answer to two decimal places.
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You should give the function to use.
For metric on Earth, h(t) = -4.9t^2 + vt + h0 is commonly used, but sometime it's -5t^2.
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h(t) = -4.9t^2 + vt + h0
For this problem:
h(t) = -4.9t^2 + 13t + 39
h(t) = -4.9t^2 + 13t + 39 = 11
It's a quadratic, solve for t, ignore the negative solution.
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