SOLUTION: the abscissa of a point p is -6 and its distance from the point q(1,3) is √74. find the ordinate of point p
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Question 926255: the abscissa of a point p is -6 and its distance from the point q(1,3) is √74. find the ordinate of point p Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! the abscissa of a point p is -6 and its distance from the point q(1,3) is √74. find the ordinate of point p
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That is really old terminology.
abscissa is the x-value
ordinate is the corresponding y-value
Your point is (-6,y)
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Equation:
(y-3)^2 + (-6-1)^2 = 74
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(y-3)^2 + 49 = 74
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(y-3)^2 = 25
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y-3 = 5 or y-3 = -5
y = 8 or y = -2
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Cheers,
Stan H.
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