Question 926175: Find all solutions for, 5 sin^2(x) plus sin(x)= cos^2(x), that lie between 0 =< x =< 2pi.
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find all solutions for, 5 sin^2(x) plus sin(x)= cos^2(x), that lie between 0 =< x =< 2pi
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5sin^2(x)+sinx=cos^2(x)
5sin^2(x)+sinx=1-sin^2(x)
6sin^2(x)+sinx-1=0
(3sinx-1)(2sinx+1)=0
3sinx-1=0
sinx=1/3
x≈0.34, 2.80
or
2sinx+1=0
sinx=-1/2
x=7π/6, 11π/6
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