SOLUTION: solve for x log5(3x-7)=2

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Question 926088: solve for x
log5(3x-7)=2
Answer by Alan3354(69443) About Me  (Show Source):
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solve for x
log5(3x-7)=2
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If 5 is the base,
log%285%2C%283x-7%29%29+=+2
log%285%2C%283x-7%29%29+=+log%285%2C5%5E2%29
3x-7 = 25
x = 32/3