SOLUTION: Edna and Nancy leave the house of a common friend at the same time and walk for 4 hours. Edna walks due east at the average rate of 4 kilometers per hour and Nancy walks due north

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Question 92606: Edna and Nancy leave the house of a common friend at the same time and walk for 4 hours. Edna walks due east at the average rate of 4 kilometers per hour and Nancy walks due north at the average rate of 3 kilometers per hour. What is the straight-line distance between them, in kilometers, at the end of the 4 hours?
Answer by psbhowmick(878) About Me  (Show Source):
You can put this solution on YOUR website!
Avg. speed of Edna = 4 kmph due East.
Distance traversed by Edna in 4 hours = 4 x 4 = 16 km due East.

Avg. speed of Nancy = 3 kmph due North.
Distance traversed by Nancy in 4 hours = 4 x 3 = 12 km due North.

So, after 4 hrs. the straight line distance between them is
sqrt%2816%5E2+%2B+12%5E2%29 = 20 km