Question 92604: The length of a rectangular garden is 1 ft less than 2 times its width. If the perimeter of the garden is 46 ft, find the dimensions of the garden.
Answer by psbhowmick(878)   (Show Source):
You can put this solution on YOUR website! Let the length of the garden be x ft and the width be y ft.
2 times width = 2y ft.
1 ft less than 2 times width = (2y - 1) ft.
This value is equal to length = x ft.
So, 2y - 1 = x
or 2y = x + 1 ________(1)
Perimeter = 2(Length + Width)
So, 46 = 2(x + y) ________ (2)
Substituting, '2y' from (1) in (2)
46 = 2x + (x + 1)
or 3x = 46 - 1 = 45
or x = 45/3
or x = 15
So, y = (15 + 1)/2 = 8
Thus, length = 15 ft and width = 8 ft.
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