Question 925972: the length of a rectangle is 3 yd less than twice the width, and the area of the rectangle is 14 yd^2. Find the dimensions of the rectangle.
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! L = 2w - 3
Lw = 14
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(2w - 3)w = 14
2ww - 3w - 14 = 0
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the above quadratic equation is in standard form, with a=2, b=-3 and c=-14
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
2 -3 -14
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the quadratic has two real roots at:
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w = 3.5
w = -2
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the negative root doesn't fit the problem statement, so use the positive root:
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answer:
w = 3.5 yd
L = 4 yd
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