SOLUTION: The width of a rectangle is one more than half its length. If the length is tripled and the width left unchanged, the new perimeter would be 58 cm. what is the area of the original

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Question 925880: The width of a rectangle is one more than half its length. If the length is tripled and the width left unchanged, the new perimeter would be 58 cm. what is the area of the original rectangle?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
The width of a rectangle is one more than half its length. If the length is tripled and the width left unchanged, the new perimeter would be 58 cm. what is the area of the original rectangle?
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original rectangle:
let x=length
1+x/2=width
new rectangle:
3x=length
1+x/2=(2+x)/2
perimeter=2*length+2*width
6x+2+x=58
7x=56
x=8
..
area of original rectangle=x(1+x/2)=8(1+4)=8*5=40 cm^2