Question 925865: How many ounces of a base metal (no silver) must be alloyed with 100 ounces of 39% silver alloy to obtain an alloy that is 15% silver?
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! base metal % in 39% silver allow = (1 - 0.39)
base metal % in 15% silver allow = (1 - 0.15)
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(1 - 0.39)*100 + 1.0*x = (1 - 0.15)*(100 + x)
61 + x = (1 - 0.15)*(100 + x)
61 + x = 0.85*(100 + x)
61 + x = 85 + 0.85x
0.15x = 24
x = 24/0.15
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answer:
x = 160 ounces of base metal
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