SOLUTION: A boy has $3.20 in nickels, dimes and quarters. There are three times as many quarters as nickels, and five more dimes than nickels. How many coins of each type does he have?
Algebra ->
Customizable Word Problem Solvers
-> Coins
-> SOLUTION: A boy has $3.20 in nickels, dimes and quarters. There are three times as many quarters as nickels, and five more dimes than nickels. How many coins of each type does he have?
Log On
Question 925793: A boy has $3.20 in nickels, dimes and quarters. There are three times as many quarters as nickels, and five more dimes than nickels. How many coins of each type does he have? Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! x the number of Nickels
25(3x) + 10(x+5) + 5x = 320
90x = 320 - 50
90x = 270
x = 3, the number of Nickels. 9 Quarters and 8 Dimes
and Checking
225 + 80 + 15 = 320
