SOLUTION: Find all solutions to the equation below in the interval [ 0 , 2pi )?
Enter your answers in increasing order (smallest to largest). Enter DNE in any unused answer blanks.
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Enter your answers in increasing order (smallest to largest). Enter DNE in any unused answer blanks.
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Question 925791: Find all solutions to the equation below in the interval [ 0 , 2pi )?
Enter your answers in increasing order (smallest to largest). Enter DNE in any unused answer blanks.
7cos(x)sin(x)+14 cos(x) = 0
Unsure how to solve
Please help Found 2 solutions by stanbon, Alan3354:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 7cos(x)sin(x)+14 cos(x) = 0
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7cos(x)[sin(x) + 2] = 0
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cos(x) = 0 or sin(x) = -2
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cos(x) = 0 yields solution x = pi/2 and x = (3/2)pi
sin(x) = 02 yields no solution as it is extraneous
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Cheers,
Stan H.
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You can put this solution on YOUR website! 7cos(x)sin(x)+14 cos(x) = 0
cos*sin + 2cos = 0
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cos*(sin + 2) = 0
cos = 0 --> x = pi/2, 3pi/2
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sin = -2
No real solution.
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