SOLUTION: tan(a)=7/sqrt(32) and pi<a<3pi/2. Find the exact value of tan (a/2). I found the cos which is sqrt(32)/9. I plugged it in the half-angle identity for tan which is +-sqrt(1-cos a/1+
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-> SOLUTION: tan(a)=7/sqrt(32) and pi<a<3pi/2. Find the exact value of tan (a/2). I found the cos which is sqrt(32)/9. I plugged it in the half-angle identity for tan which is +-sqrt(1-cos a/1+
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You can put this solution on YOUR website! tan(a)=7/sqrt(32) and pi
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*** cos is negative in Q3. cos(a) = -sqrt(32)/9
Use tan(a/2) = sin(a)/(1 + cos(a))
sin(a) = -7/9
tan(a/2) =
= -7/(9 - sqrt(32))
=
