SOLUTION: How would I solve the dimensions of a rectangle if the length is 3cm more than the width and the diagonal is 15cm?
I'm supposed to use factored form for the problem but I haven'
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I'm supposed to use factored form for the problem but I haven'
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Question 925562: How would I solve the dimensions of a rectangle if the length is 3cm more than the width and the diagonal is 15cm?
I'm supposed to use factored form for the problem but I haven't been able to solve it. I know it has something to do with isolating w.
So far, I've subbed in w + 3 for the length and tried pythagorean theorem. But that answers keep coming up wrong. They should be 12 by 9. Found 2 solutions by josgarithmetic, srinivas.g:Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website! Let width be w cm
length = (w+3) cm
diagonal = 15 cm
as per pythagorean theorem
move 225 to the right
on dividing with 2 both sides
(w-9) =0 or (w+12 )= 0
w=9 or w=-12
w cannot be negative
so w= 9
l = w+3 = 12
so length = 12 cm
width = 9 cm