6y-12=0
When you have an equation of a line with only one letter in it
like this, one way to graph it is to add 0 times the missing
letter to it. In this case x is missing, so add 0x to the
equation. That is, make it:
0x+6y-12=0
Now make a table of values, substituting different arbitrary values
for the missing letter:
x | y
-----
0 |
1 |
-3 |
5 |
Substitute x=0: Substitute x=1: Substitute x=-3 Substitute x=5
0x+6y-12=0 0x+6y-12=0 0x+6y-12=0 0x+6y-12=0
0(0)+6y-12=0 0(1)+6y-12=0 0(-3)+6y-12=0 0(5)+6y-12=0
0+6y-12=0 0+6y-12=0 0+6y-12=0 0+6y-12=0
6y-12=0 6y-12=0 6y-12=0 6y-12=0
6y=12 6y=12 6y=12 6y=12
y=2 y=2 y=2 y=2
Now we have filled in the table:
x | y
-----
0 | 2
1 | 2
-3 | 2
5 | 2
So we plot the points (0,2), (1,2), (-3,2), and (5,2)
Now draw a line through them:
Can you think of an easier way to do this when there is a missing letter
in your equation?
If not, it's OK, for this way will always work.
Edwin
