SOLUTION: a parabola has a vertex v=(6, 4) and a focus f=(6, -1). Enter the equation in the form: (x-h)^2=4p(y-k) or (y-k)^2=4p(x-h)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: a parabola has a vertex v=(6, 4) and a focus f=(6, -1). Enter the equation in the form: (x-h)^2=4p(y-k) or (y-k)^2=4p(x-h)      Log On


   

Question 925550: a parabola has a vertex v=(6, 4) and a focus f=(6, -1). Enter the equation in the form: (x-h)^2=4p(y-k) or (y-k)^2=4p(x-h)
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
You are given enough information to find the directrix. Use the distance formula and definition of a parabola to derive the equation for the specific parabola of your example; and adjust the form of the equation to whichever format you want.

The directrix is on the other side of the vertex than the focus. The directrix is y=9, so the general point for the directrix would be (x,9).

Work with this:
Focus to parabola equals directrix to parabola.