SOLUTION: Distance rate time problem I think. Tried making that chart thing but don't know what to put where in it and can't figure it out.
Hank goes 10 mph in still water. He notices on
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-> SOLUTION: Distance rate time problem I think. Tried making that chart thing but don't know what to put where in it and can't figure it out.
Hank goes 10 mph in still water. He notices on
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Question 925262: Distance rate time problem I think. Tried making that chart thing but don't know what to put where in it and can't figure it out.
Hank goes 10 mph in still water. He notices one day he goes 4 miles upstream in the same amount of time he goes downstream. What is the approximate speed of that day? Found 2 solutions by Alan3354, stanbon:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Hank goes 10 mph in still water. He notices one day he goes 4 miles upstream in the same amount of time he goes downstream. What is the approximate speed of that day?
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Speed of what?
You can put this solution on YOUR website! Hank goes 10 mph in still water. He notices one day he goes 4 miles upstream in the same amount of time he goes downstream. What is the approximate speed of that day?
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Upstream DATA:
distance = 4 miles ; rate = 10-c ; time = d/r = 4/(10-c) hrs
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Downstream DATA:
distance = 4 miles ; rate = 10+c ; time = d/r = 4/(10+c) hrs
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Equation:
4/(10-c) = 4/(10+c)
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Comment:: Either the speed of the current is zero or
his distance downstream is different then his distance
upstream. Please check your problem statement.
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Cheers,
Stan H.
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