SOLUTION: the product of my three digits is 15. The sum of the first and third digit is 1 less than the second digit. The sum of the second and third digit is twice as large as the first dig

Algebra ->  Test -> SOLUTION: the product of my three digits is 15. The sum of the first and third digit is 1 less than the second digit. The sum of the second and third digit is twice as large as the first dig      Log On


   

Question 925243: the product of my three digits is 15. The sum of the first and third digit is 1 less than the second digit. The sum of the second and third digit is twice as large as the first digit. Who am I?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

the product of my three digits is 15, that is digits are 1,3,5

h (1st digit), t(2nd digit) u (3rd digit)

Question States...

h + u = t-1  0r  t = h + u + 1   (t must be 5)     5 = 1 + 3 + 1   

t + u = 2h   0r t = 2h-u   5 = 2*3 - 1  , u = 1 and h = 3

351 the number