There are two ways to do it. Without algebra and with algebra.
First way: without algebra:
In a two-digit number, the digit in the tens place is three times the digit in the one place.
That narrows it down to 31, 62, or 93
The sum of the digit is four more than the difference of the digit.
The sum and difference of the digits of 31 are 2 and 4. That's not it because
4 isn't 4 more than 2.
The sum and difference of the digits of 62 are 4 and 8. That's it because
8 is 4 more than 2.
So the answer is 62.
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Second way: with algebra:
In a two-digit number, the digit in the tens place is three times the digit in the one place.
t = 3u
The sum of the digit is four more than the difference of the digit.
t+u = t-u+4
Subtract t from both sides
u = -u+4
Add u to both sides
2u = 4
Divide both sides by 2
u = 2
Substitute in
t = 3u
t = 3(2)
t = 6
What is the number?
The number is 62.
Edwin
