SOLUTION: a 60% saline solution is to be mixed with an 80% saline solution to get 40 liters of a 65% saline solution. how many liters of the 60% and 80% solution should be used
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Question 925090: a 60% saline solution is to be mixed with an 80% saline solution to get 40 liters of a 65% saline solution. how many liters of the 60% and 80% solution should be used Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! x = liters of 60% solution
y = liters of 80% solution
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60x + 80y = 65*40
x + y = 40
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put the system of linear equations into standard form
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60x + 80y = 2600
x + y = 40
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copy and paste the above standard form linear equations in to this solver:
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answer:
x = liters of 60% solution = 30
y = liters of 80% solution = 10
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