Question 924906: [Jonathan and Lisa are both attending an overnight camp. Jonathan rides the bus, which averages 36 mph and left the high school at 4 pm. Lisa was running late and showed up at the high school at 4:30 pm. If she follows the same path as the bus and averages 53 mph, how long will she be traveling until she catches up to the bus? How long will Jonathan have been traveling on the bus when Lisa catches up to him?]
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! Lisa's speed relative to the bus = ?
53 - 36 = 17 mph
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s = d/t
d = st
t = d/s
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how much time the bus had been driving when Lisa left school = ?
4:30 - 4:00 = 0:30 = 0.5 hr
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distance traveled by the bus when Lisa left school = ?
36 * 0.5 = 18 miles
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time Lisa will drive before she catches up to the bus = ?
18/17
1.05882352941
1 hour and (0.05882352941)*60 minutes
1 hour 3.5 minutes
1 hour 3 minutes 30 seconds
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time Jonathan has been traveling on the bus when Lisa catches up to him = ?
0.5 + 1.05882352941
1.55882352941
1 hour 33 minutes 30 seconds
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