SOLUTION: what is the vertex form of the function y=3x^2-12x+17?

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Question 924850: what is the vertex form of the function y=3x^2-12x+17?
Found 2 solutions by ewatrrr, stanbon:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

finding the vertex form of a Parabola opening up(a>0) or down(a<0),
y=a%28x-h%29%5E2+%2Bk
y = ax^2 + bx + c ⇒ y = a(x -(-b/2a)^2) - a(-b/2a)^2 + c
........
y=3x^2-12x+17 format ax^2 + bx + c
Note: -%28-12%2F%282%2A3%29%29 = 2
........
y = 3(x-2)^2 -12 + 17
y = 3(x-2)^2 + 5

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
what is the vertex form of the function y=3x^2-12x+17?
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y-17 = 3x^2-12x
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Factor and complete the square to get::
y-17 = 3(x^2-4x+4) - 12
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Add 12 to both sides to get::
y-5 = 3(x-2)^2
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vertex:: (2,5)
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Cheers,
Stan H.
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