SOLUTION: Please help. A rectangle is 3 times as long as it is wide. If the length is increased by 6 and the width by 8, the area is increased by 108. Find the perimeter of the original rect

Algebra ->  Rectangles -> SOLUTION: Please help. A rectangle is 3 times as long as it is wide. If the length is increased by 6 and the width by 8, the area is increased by 108. Find the perimeter of the original rect      Log On


   

Question 924813: Please help. A rectangle is 3 times as long as it is wide. If the length is increased by 6 and the width by 8, the area is increased by 108. Find the perimeter of the original rectangle. Thanks for your help.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

     .

A = Lw

Original: L = 3w and width = w

(3w+6)(w+8) - (3w)w = 108

3w^2 + 3w + 48 - 3w^2 = 108

3w = 60

w = 20  and L = 60 3%2A20

....

2L + 2w = P

120 + 40 = 160 units