SOLUTION: Determine algebraically the solution set to the following quadratic-quadratic system of equations. Y=-2x^2-3x+3 Y=-x^2-x+7/4

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Question 924709: Determine algebraically the solution set to the following quadratic-quadratic system of equations.
Y=-2x^2-3x+3
Y=-x^2-x+7/4
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Set them equal to each other and solve for x.
-2x%5E2-3x%2B3=-x%5E2-x%2B7%2F4
-x%5E2-2x%2B5%2F4=0
4x%5E2%2B8x-5=0
%282x-1%29%282x%2B5%29=0
Two solutions:
2x-1=0
2x=1
x=1%2F2
and
2x%2B5=0
2x=-5
x=-5%2F2
Now that you have the x-coordinates, plug into either equation to find the matching y-coordinates.