SOLUTION: log2(x)+log2(x-4)=log2(x+24) solve for X

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Question 924647: log2(x)+log2(x-4)=log2(x+24)
solve for X
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
log2(x)+log2(x-4)=log2(x+24)
solve for X
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log%282%2C%28x%29%29%2Blog%282%2C%28x-4%29%29=log%282%2C%28x%2B24%29%29%29
log%282%2C%28x%29%29%2Blog%282%2C%28x-4%29-log%282%2C%28x%2B24%29%29%29=0
log%282%2C%28x%29%28x-4%29%2F%28x%2B24%29%29=0
base(2) raised to log of number(0)=number(x)(x-4)/(x+24))
2^0=(x)(x-4)/(x+24))
(x^2-4x)/(x+24)=1
(x^2-4x)=(x+24)
x^2-5x-24=0
(x-8)(x+3)=0
x=-3 (reject)
x=8