You can
put this solution on YOUR website!
"The DISTANCE is the DISTANCE (in absolute value)"
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-15 -14 -13 -12 -11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4
Let x be a variable that can take on any value that is within 5 units of -6.
Then the DISTANCE from any value of x to -6 is the DIFFERENCE (in absolute
value. The DIFFERENCE is x-(-6) and in absolute value is |x-(-6)| and we
can simplify that to |x+6| and to make that distance (difference) less that
5 units we write
|x+6| < 5
You can also do it by starting with the inequality looking at the
number line above:
-11 < x < -1
Then add the opposite of -6, which is +6 to all three sides:
-11+6 < x+6 < -1+6
-5 < x+6 < 5
|x+6| < 5
Edwin