Question 924335: Michael swam 4 kilometers against the current in the same amount of time it took him to swim 16 kilometers with the current. The rate of the current was 3 kilometers per hour. How fast would Michael swim if there were no current?
Having a really hard time setting up a solvable equation, could you help solve.
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! x = mike speed
y = current speed = 3 kph
---
up stream:
x - y = 4/t
x = 4/t + y
---
down stream:
x + y = 16/t
x = 16/t - y
---
x = 4/t + y
x = 16/t - y
4/t + y = 16/t - y
2y = 12/t
y = 6/t
---
y = 3
y = 6/t
3 = 6/t
t = 2
---
x = 4/t + y
x = 4/t + 3
x = 4/2 + 3
x = 2 + 3
---
answer:
x = 5 mph
---
Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---
Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
---
Convert fractions, decimals, and percents:
https://sooeet.com/math/fraction-decimal-percent.php
---
Calculate and graph the linear regression of any data set:
https://sooeet.com/math/linear-regression.php
|
|
|
