SOLUTION: A passenger train traveled 110 miles in the same amount of time it took a freight train to travel 90 miles. The rate of the freight train was 10 miles per hour slower than the rate
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Question 924285: A passenger train traveled 110 miles in the same amount of time it took a freight train to travel 90 miles. The rate of the freight train was 10 miles per hour slower than the rate of the passenger train. Find the rate of the passenger train Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! x = speed of passenger train
y = speed of freight train
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s = d/t
t = d/s
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x = 110/t
y = 90/t
y = x - 10
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y = 90/t
x - 10 = 90/t
x = 90/t + 10
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x = 90/t + 10
x = 110/t
90/t + 10 = 110/t
20/t = 10
t = 2 hours
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answer:
x = 110/t
x = 110/2
x = speed of passenger train = 55 mph
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y = 90/t
y = 90/2
y = speed of freight train = 45 mph
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