SOLUTION: two times the father's age is 8 more than six times his son's age. ten years ago, the sum of their age was 44. the age of the son is:

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Question 924196: two times the father's age is 8 more than six times his son's age. ten years ago, the sum of their age was 44. the age of the son is:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
x the son's age and y the Father's age
(y - 10) + (x-10) = 44
y = -x+%2B+64
2(-x+64) = 6x + 8
-2x + 128 = 6x + 8
120 = 8x
15 = x, the son's age
............
and...checking (Father's age 49)
2y = 6x + 8
98 = 90 + 8