SOLUTION: If the divisor is x+4, the quotient is 2x+3, and the remainder is 5, find the dividend (or the polynomial being divided).

Algebra ->  Human-and-algebraic-language -> SOLUTION: If the divisor is x+4, the quotient is 2x+3, and the remainder is 5, find the dividend (or the polynomial being divided).      Log On


   

Question 924158: If the divisor is
x+4,
the quotient is
2x+3,
and the remainder is
5,
find the dividend (or the polynomial being divided).
Found 3 solutions by ewatrrr, MathLover1, MathTherapy:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

(x + 4)(2x+3) +  = 2x^2 + 11x + c = 2x^2 + 11x + 17

Using synthetic Division:  c = 17

-4	2	11	17

		-8	-12

	2	3	5

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
Dividends} and divisors are the two key ingredients that yield the quotient, or answer, to a division problem.
The dividend is the number being divided, while the divisor is the number by+which the dividend is divided.
In other words, given a%3Ab or a%2Fb , a is the dividend and b is the divisor, and qquotient
so, you are given:
the divisor is
b=x%2B4
the quotient is
q=2x%2B3
and the remainder is 5,
a%2Fb=q=>a=q%2Ab since you have remainder 5 you need to add it to the q%2Ab
a=q%2Ab%2B5...substitute q and b
a=%282x%2B3%29%2A%28x%2B4%29%2B5
a=%282x%5E2%2B8x%2B3x%2B12%29%2B5
a=2x%5E2%2B11x%2B17.......the polynomial being divided


Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

If the divisor is
x+4,
the quotient is
2x+3,
and the remainder is
5,
find the dividend (or the polynomial being divided).


Dividend: highlight_green%282x%5E2+%2B+11x+%2B+17%29

You can do the check!! 

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