SOLUTION: conic sections circles. given the equation x^2+(y-3)^2=25. A) what is the center c? b.) what is the radius r?

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Question 924146: conic sections circles. given the equation x^2+(y-3)^2=25. A) what is the center c? b.) what is the radius r?

Answer by Edwin McCravy(20065) About Me  (Show Source):
You can put this solution on YOUR website!
You must memorize this:

(x-h)2 + (y-k)2 = r2

And that the center is (h,k) and the radius is r

Your equation is

x2 + (y-3)2 = 25

You want to rewrite it so that looks like this:

(x-h)2 + (y-k)2 = r2

To make x look like (x-h) write it as (x-0)
(y-3) already looks like (y-k)
To make 25 look like r2, write it as 52

Then you have this equation:

(x-0)2 + (y-3)2 = 52

And when you compare it to this equation which you memorize, 

(x-h)2 + (y-k)2 = r2

And you see that -0=-h or h=0, and -3=-k or k=3 and r2=52
and so r=5.

So the center is (h,k) = (0,3) and radius = r = 5.  The graph is 



Edwin