SOLUTION: Ryan traveled to the ferry office and back. It took one hour less time to get there than it did to get back.The average speed on the trip there was 25 mph. The average speed on the
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Question 924103: Ryan traveled to the ferry office and back. It took one hour less time to get there than it did to get back.The average speed on the trip there was 25 mph. The average speed on the way back was 20 mph. How many hours did the trip there take? Found 2 solutions by TimothyLamb, MathTherapy:Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! y = round trip distance to office
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go to office:
time = x
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return from office:
time = x + 1
s = d/t
20 = (y/2)/(x + 1)
20(x + 1) = (y/2)
40(x + 1) = y
40x + 40 = y
40x - y = -40
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s = d/t
25 = y/(x + x + 1)
25 = y/(2x + 1)
25(2x + 1) = y
50x + 25 = y
50x - y = -25
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put the system of linear equations into standard form
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40x - y = -40
50x - y = -25
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = time to go to office = 1.5 hours
x + 1 = time to return from office = 2.5 hours
2x + 1 = total round trip time to office = 4 hours
y = round trip distance to office = 100 miles
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Solve systems of linear equations up to 6-equations 6-variables:
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You can put this solution on YOUR website!
Ryan traveled to the ferry office and back. It took one hour less time to get there than it did to get back.The average speed on the trip there was 25 mph. The average speed on the way back was 20 mph. How many hours did the trip there take?
Let time taken to get to office, be T
Then time taken to get back is: T + 1
Distance there and back are equal
Therefore, we get: 25T = 20(T + 1)
25T = 20T + 20
25T – 20T = 20
5T = 20
T, or time taken to get to office = , or hours
